X^2+33x-380=0

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Solution for X^2+33x-380=0 equation: 



X^2+33X-380=0

a = 1; b = 33; c = -380;
Δ = b2-4ac
Δ = 332-4·1·(-380)
Δ = 2609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{2609}}{2*1}=\frac{-33-\sqrt{2609}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{2609}}{2*1}=\frac{-33+\sqrt{2609}}{2}
$

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